9h^2+16h-14=h

Solution for 9h^2+16h-14=h equation:

9h^2+16h-14=h

We move all terms to the left:

9h^2+16h-14-(h)=0

We add all the numbers together, and all the variables

9h^2+15h-14=0

a = 9; b = 15; c = -14;
Δ = b2-4ac
Δ = 152-4·9·(-14)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-27}{2*9}=\frac{-42}{18}
=-2+1/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+27}{2*9}=\frac{12}{18}
=2/3
$